Anything and everything goes in here... within reason.
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Sun Jun 19, 2005 5:39 am

Yeh but did you get it using a table? I dont understand how (other than trial and error) I can do it with a table.

Sun Jun 19, 2005 10:16 pm

zorg wrote:^_^ I cant table this answer..

A farmer buys 100 live animals for $100, how many of each does he buy if chickens are 50cents each, goats are 3.50 each and sheep are $10 each.

Theres loads of different answers yeh?

Show how a table can be used to solve this question

I hate tables, why couldn't he just buy 10 goddamn sheep and be done with it!


Well this is how I see it -

All the solutions can be sorted into 11 sections - solutions with no sheep, one sheep, two sheep etc. until you get to 10 sheep.

For no goats we have $100 left and we can split this further into 29 solutions, no goats, one goat, two goats etc. until we get to 28 goats and as the number of goats increase obiously the number of chickens decrease.

For one goat we have $90 left and we can split this into 26 solutions - no goats etc. until we reach 25 goats and do te same as above.

For the rest I will just put -

(Number of sheep bought) - (Money left after buying the sheep) - (Number of solutions available for this amount of sheep)

0 - 100 - 29
1 - 90 - 26
2 - 80 - 23
3 - 70 - 21
4 - 60 - 18
5 - 50 - 15
6 - 40 - 12
7 - 30 - 9
8 - 20 - 6
9 - 10 - 3
10- 0 - 0
Total - 162 solutions

The way I worked out the number of solutions for each sheep was for the amount of money available, I divided it by 3.5 to see the maximum amount of goats I could buy with the money and added one for a scenario where no goats where bought.

--------

I tried to explain it as well as possible but if you still need help just PM me.

The data above could maybe be passed of as a table but I'm too sleepy to think of how else it could be put into a table :)

Sun Jun 26, 2005 3:03 pm

How to find the term that is independent of x from the equation [x+1/(x^2)]^18? I know how to find the answer, I just want to know the shortcut.

Sun Jun 26, 2005 4:57 pm

You have a top view of the North Pole, and there are numbers from the top going clockwise 1-4 like so:
.....1.....
.4.......2.
.....3.....

A foucalt pendulum is found at the North Pole, set in to motion so that it traces a line from two to four. In six hours, between what two numbers will the pendulum trace?

My teacher says its 1 and 4, but I'm very determined to prove to her that its 1 and 3. help?

Mon Jun 27, 2005 1:26 pm

Anoohilator wrote:
zorg wrote:^_^ I cant table this answer..

A farmer buys 100 live animals for $100, how many of each does he buy if chickens are 50cents each, goats are 3.50 each and sheep are $10 each.

Theres loads of different answers yeh?

Show how a table can be used to solve this question

I hate tables, why couldn't he just buy 10 goddamn sheep and be done with it!


Well this is how I see it -

All the solutions can be sorted into 11 sections - solutions with no sheep, one sheep, two sheep etc. until you get to 10 sheep.

For no goats we have $100 left and we can split this further into 29 solutions, no goats, one goat, two goats etc. until we get to 28 goats and as the number of goats increase obiously the number of chickens decrease.

For one goat we have $90 left and we can split this into 26 solutions - no goats etc. until we reach 25 goats and do te same as above.

For the rest I will just put -

(Number of sheep bought) - (Money left after buying the sheep) - (Number of solutions available for this amount of sheep)

0 - 100 - 29
1 - 90 - 26
2 - 80 - 23
3 - 70 - 21
4 - 60 - 18
5 - 50 - 15
6 - 40 - 12
7 - 30 - 9
8 - 20 - 6
9 - 10 - 3
10- 0 - 0
Total - 162 solutions

The way I worked out the number of solutions for each sheep was for the amount of money available, I divided it by 3.5 to see the maximum amount of goats I could buy with the money and added one for a scenario where no goats where bought.

--------

I tried to explain it as well as possible but if you still need help just PM me.

The data above could maybe be passed of as a table but I'm too sleepy to think of how else it could be put into a table :)


Thanks. Turns out it was just trial and error... really misleading >.< You expect things to be hard ya know? lol. Thanks for that tho!

Mon Jun 27, 2005 7:38 pm

(*Dranzer*) wrote:You have a top view of the North Pole, and there are numbers from the top going clockwise 1-4 like so:
.....1.....
.4.......2.
.....3.....

A foucalt pendulum is found at the North Pole, set in to motion so that it traces a line from two to four. In six hours, between what two numbers will the pendulum trace?

My teacher says its 1 and 4, but I'm very determined to prove to her that its 1 and 3. help?


Well, you might think that in 24 hours, the pendulum will move in a position relative to the center that is 360 degrees. (The pendulum doesn't move, mind you, but it's all relative). Fortunately for you, that's the case, but it's only true at the north pole.

And the basic formula behind the foucault pendulum is Twist = (360)(sin theta), where twist is measured in degrees, and theta is latitude. Multiply by 1/4, and you can determine how many degrees the pendulum will swing in six hours at any given latitude. Lay that over your four-point compass above, and that will tell you where the pendulum is.

Mon Jun 27, 2005 10:51 pm

843 wrote:How to find the term that is independent of x from the equation [x+1/(x^2)]^18? I know how to find the answer, I just want to know the shortcut.


Could you rephrase the question; I don't exactly understand what you're asking. Or perhaps you could give the answer and I could see from that what the question was.

Wed Jun 29, 2005 11:30 pm

shapu wrote:
(*Dranzer*) wrote:You have a top view of the North Pole, and there are numbers from the top going clockwise 1-4 like so:
.....1.....
.4.......2.
.....3.....

A foucalt pendulum is found at the North Pole, set in to motion so that it traces a line from two to four. In six hours, between what two numbers will the pendulum trace?

My teacher says its 1 and 4, but I'm very determined to prove to her that its 1 and 3. help?


Well, you might think that in 24 hours, the pendulum will move in a position relative to the center that is 360 degrees. (The pendulum doesn't move, mind you, but it's all relative). Fortunately for you, that's the case, but it's only true at the north pole.

And the basic formula behind the foucault pendulum is Twist = (360)(sin theta), where twist is measured in degrees, and theta is latitude. Multiply by 1/4, and you can determine how many degrees the pendulum will swing in six hours at any given latitude. Lay that over your four-point compass above, and that will tell you where the pendulum is.


Thank you, but I don't see how my teacher got one and four. It seems very illogical for a pendulum stationed at the center to move back and forth without even getting close to the center.

Thu Jun 30, 2005 2:23 pm

It's possible she meant one and three and misspoke.

Thu Jun 30, 2005 3:41 pm

No, she repeated herself several times for days when I bugged her.

Thu Jun 30, 2005 9:44 pm

Then she's just wrong.

Thu Jun 30, 2005 11:31 pm

Thanks for the back up 8)

Sun Jul 17, 2005 10:28 pm

I need to solve the following equation,

1600 = .25^n-1 (to the power of N minus 1)

I know how to solve it (The process and all) but I don't know how to simply 1600 so it can be .25 to the power of something. That way, I could equate the exponents and get n.

Can anyone help me?

Sun Jul 17, 2005 10:45 pm

Ammer wrote:I need to solve the following equation,

1600 = .25^n-1 (to the power of N minus 1)

I know how to solve it (The process and all) but I don't know how to simply 1600 so it can be .25 to the power of something. That way, I could equate the exponents and get n.

Can anyone help me?


First, using prime factors, you get out that 1600 = 2^6 x 5^2.

So, then we try to work out 25 in terms of powers of two.

25 = 2^x

.'. log2 25 = x
.'. (log 25)/(log 2) = x
.'. x = 4.64385619

.'. 1600 = 2^6 x 2^4.64385619
.'. 1600 = 2^10.64385619
.'. 1600 = 4^5.32192809

Think that works, and hope that is all clear. If you're confused about any of it, just ask :)

Sun Jul 17, 2005 10:53 pm

Hey, I need a bit of language help. French, that is.

My teacher's explained the concept of imparfait to us, and that you use it to describe something that 1/ happens repetitively, 2/ regards emotion, 3/ regards mental state, 4/ regards physical state, or 5/ is a developing action.

All this versus passé composé which has to do with a completed action or something that happens in a defined time.

However, all that seems to confuse the heck out of me and I'm overanalysing everything. If possible, can anyone please define things...better, I suppose? :\
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