Pink Poogle Toy Forum

Okay. Try it this way.

Pretend that x=y+1. Just to make the problem "easier."

So that would be yx + 2x

Now, since they are both in terms of x, add them.

(y+2)x

Now replace x with y+1.

(y+2)(y+1)

I'm a bad teacher.

Hmm...he's got it right, although the first time I read it, it was confusing. :P

y(y+1) + 2(y+1)

When you have two like sets of bracketed numbers, reduce it to one set. Think about it this way. If you had the equation x+2x+3x+4x, the like term is x, so you factor it out. It would become x(1+2+3+4), or rather, 10x.

So, the like term in your equation is (y+1). Remove that from both sides and place it at the front, so you get...

y(y+1) + 2(y+1)
.----'-----------'
v
(y+1) y + 2
(y+1)(y+2)

[edit] Whoops, he beat me to it. :P Eh well.

_________________

Oooooh, I get it now! Thanks Yoshi and o_0!

_________________

Zero set 13 of 26

ok trig time!
identities, like cos^2+sin^2=1 and tan^2+1=sec^2
(im leaving out the theta/x/whatever for the angle to make it less confusing. so cos is actually cos(x))
aiight.

prove the given identity:
sin/(sin+cos) = tan/(1+tan)
working with the right side, what i have so far is knowing that 1=cos^2+sin^2. so tan/(cos^2+sin^2+tan)
or, alternatively, tan/(cos^2+sin^2+sin/cos)

im lost.

_________________

March is Women's History Month!

sin/(sin+cos) = tan/(1+tan)

Put everything into terms of sin and cos.

sin/(sin+cos) = (sin/cos)/(1+[sin/cos])
sin/(sin+cos) = (sin/cos)/([cos/cos]+[sin/cos])
sin/(sin+cos) = (sin/cos)/([sin+cos]/cos)

Dividing is the same as multiplying by the reciprocal.

sin/(sin+cos) = (sin/cos) * (cos/[sin+cos])
sin/(sin+cos) = (sin*cos)/(cos * [sin+cos])

The two cosines cancel.

sin/(sin+cos) = sin/(sin+cos)

Oh, and here were the identities I used.

tan = (sin/cos)
x/x = 1

Well, the second one really wasn't an identity, but, meh.

beautiful. thank you so much.

_________________

March is Women's History Month!

Okay I have a science problem. I dont have too long to solve this. This is a Physics problem

There is a pendulum. As the length of the pendulum is increased, so is the period of one swing. I need figure out the general sceince idea behind this relationship. Think forcec, energy and potention energies and such. Thanks for any perspectives.

_________________

Visit the PPT Better than You

*tries to dig up 6th grade physical science*

Well, the pendulum has to travel a longer distance, and if everything falls at the same rate, it would mathematically take longer. Maybe it has to overcome gravity for a greater time, hence slower and longer.

Hopefully I haven't said anything incorrect...

_________________

Who loves me a lot and wants to help me with rotating conics?
Since I can't figure out a better way to convey it, $$numbershere$$ = square root of the numbers. ($$4$$=2).

I need to put it into standard form and graph, but I can probably figure out the last part on my own.

2x^2 - $$3xy$$ + y^2 - 20 = 0

I know it's kind of an awful problem, so major thanks to anyone who helps.

_________________

What is the Japanese word for 'spirit summoner'?

Can anyone help me out with Geometry? I had this problem on a quiz i just failed and I have no idea how to figure it out..



I don't know how I would solve for it. That chapter we learned about tangents and chords and stuff so I guess they'll have to help you out somehow.

edit: btw the answer is 10, but I need to know how to solve for it @_@

_________________

I got 10, this is what I did:

I drew a line from the center to the edge, making it connect to the 8 line.

<img src="http://img.photobucket.com/albums/v398/neko_kurisutaru/circle.jpg" alt="Image hosted by Photobucket.com">

Then if you look it's the same as X because they both go from the center to the edge. So I labeled the new line X. Then you can see that the 8 and six line form a right angle. So you have two lengths of a right triangle.

So then I did:

a(squared)+ b(squared)= x(squared)
64+ 36= 100

The square root of 100 is 10. so X= 10. I'm not sure if that was the way you were "supposed" to do it, but that's how I do those problems. I hope that helped.

This is assuming that the length from the edge of the circle to where the 6 line hits the other line is 8 and not the whole thing.

_________________

Set by Moogie

Hi. Since I am absolutely terrible at writing introductions and conclusions... I need both for an essay about the abstract artist Jackson Pollock. Just give me some ideas or something (or write it for me to be nice). Yeah, the essay is due tomorrow, and I can write everything else... but I just need those two things.

_________________

Zero set 13 of 26

Hi.

Well this is me,Callie and *Chellie.

We have speeches due on tuesday and are having trouble finding information.

We're looking for topics on Animals and Dreaming..such as if Animals have dreams/nightmares etc.

Thanks for any help

_________________

Awesome set by Tomatie

http://www.anapsid.org/ethology3.html

_________________

the greatest love story never told.