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PostPosted: Sun Apr 17, 2005 1:33 pm 
Beyond Godly
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(*Dranzer*) wrote:
There are three cyborgs in a 3-way pistol duel. The first cyborg can hit the mark each time, the second cyborg 50%, and the last one 33%. Each one is clearly marked. Who has the greatest chance of survival? Why?

All three, pistols can't kill cyborgs (conventionally speaking :P).

Either that or the 100% one, I guess.


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PostPosted: Sun Apr 17, 2005 2:24 pm 
Beyond Godly
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the first cyborg. it always hits.
though i guess itd help if the other two had infinite ammo cheat, and the first had none, that might mess the odds up a bit.


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PostPosted: Mon Apr 18, 2005 4:24 am 
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The 33% one.

1st round, the 100% shooter will pick the biggest threat -- 50%. So 50% is dead.

If it goes to the second round, then 33% is dead too . . . but with both the 1 out of 2 shooter and the 1 out of 3 shooter picking their biggest threat, it's a better-than-even chance that it won't go to a second round because 100% is dead too..

The only one who doesn't have any chance at all is 50%. (Unless someone switches the signs.)


hiddenneggs / Will
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PostPosted: Mon Apr 18, 2005 6:10 am 
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Here's my riddle:

One day, you decided to walk into the most scariest place in your whole neighborhood. You turn on the lights, but all of a sudden, they flicker and turn pitch black.
Situation: You have a lantern, a candle, and a paper bag. You only have one match(to lighten the whole place). Which one do you lighten up?


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PostPosted: Mon Apr 18, 2005 6:40 am 
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KPpinky05 wrote:
Here's my riddle:

One day, you decided to walk into the most scariest place in your whole neighborhood. You turn on the lights, but all of a sudden, they flicker and turn pitch black.
Situation: You have a lantern, a candle, and a paper bag. You only have one match(to lighten the whole place). Which one do you lighten up?


burn the bag then put fire to the candle and then the lantern
what i would do :D


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PostPosted: Mon Apr 18, 2005 7:45 am 
Beyond Godly
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KPpinky05 wrote:
Here's my riddle:

One day, you decided to walk into the most scariest place in your whole neighborhood. You turn on the lights, but all of a sudden, they flicker and turn pitch black.
Situation: You have a lantern, a candle, and a paper bag. You only have one match(to lighten the whole place). Which one do you lighten up?

The match. :P
hiddenneggs wrote:
The 33% one.

1st round, the 100% shooter will pick the biggest threat -- 50%. So 50% is dead.

If it goes to the second round, then 33% is dead too . . . but with both the 1 out of 2 shooter and the 1 out of 3 shooter picking their biggest threat, it's a better-than-even chance that it won't go to a second round because 100% is dead too..

The only one who doesn't have any chance at all is 50%. (Unless someone switches the signs.)

But that's based on the assumption that each cyborg picks the largest threat to target, which was not specifically stated in the question.


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PostPosted: Mon Apr 18, 2005 8:11 am 
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Qanda wrote:
hiddenneggs wrote:
The 33% one.

1st round, the 100% shooter will pick the biggest threat -- 50%. So 50% is dead.

If it goes to the second round, then 33% is dead too . . . but with both the 1 out of 2 shooter and the 1 out of 3 shooter picking their biggest threat, it's a better-than-even chance that it won't go to a second round because 100% is dead too..

The only one who doesn't have any chance at all is 50%. (Unless someone switches the signs.)

But that's based on the assumption that each cyborg picks the largest threat to target, which was not specifically stated in the question.

Yes, I'm making the assumption that each will attempt to maximize its own survival, despite being required to participate in the gunfight. Between half (or thereabouts) human & half computer/robot, I'm assuming some intelligence, the ability to think.

(Of course, it could be that each is disgusted at being a cyborg, and will take the opportunity to kill itself. The 100% shooter thus dies immediately, and the other two eventually will, but the 33% is still likely to live the longest, so I'll stick with my answer.)

It also isn't specifically stated in the question that a meteorite doesn't crash and kill them all, but I guess we have to make some assumptions.


hiddenneggs / Will
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PostPosted: Mon Apr 18, 2005 10:26 am 
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I've got a good one, I think:

When you say my name I disapper(sp?) what am I


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PostPosted: Mon Apr 18, 2005 10:29 am 
Way Beyond Godly
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Silence


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PostPosted: Mon Apr 18, 2005 10:31 am 
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Yup! Good job! It took me a few days to figure out that one, but you already knew it i'm guessing?


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PostPosted: Mon Apr 18, 2005 10:35 am 
Way Beyond Godly
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Never heard it before :P


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PostPosted: Mon Apr 18, 2005 2:07 pm 
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ok, i got one my uncle told me in Canada last summer:

i have a barrel and put something in it, making it all weigh 50kg. i put something else in and it now weighs 20kg.

what did i put in the second time?! o_O


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PostPosted: Mon Apr 18, 2005 3:06 pm 
Beyond Godly
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raylene wrote:
ok, i got one my uncle told me in Canada last summer:

i have a barrel and put something in it, making it all weigh 50kg. i put something else in and it now weighs 20kg.

what did i put in the second time?! o_O

A hole.

I'm still curious to know the correct answer to the cyborg question...


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PostPosted: Mon Apr 18, 2005 4:06 pm 
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Location: Malta...an island far far away...okay it in the Med sea but a girl can dream right?!
awh you knew that already Qanda! :(

ok much harder now (for me at least 0:) )

What row of numbers comes next?
1
11
21
1211
111221
312211
13112221


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PostPosted: Mon Apr 18, 2005 6:48 pm 
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Qanda, hiddenneggs is right for the cyborg one.

The first cyborg will clearly shoot at the 50% cyborg, killing it.
the 50% cyborg will know this, and to get back at the first cyborg will choose to shoot the first cyborg.
the 33% cyborg will know the 50% cyborg will die and shoot the first cyborg.

thus 50% is doomed the die. Now 2/3rds of the time one of the toher two cyborgs will hit their target, causing the first cyborg to die 66% of the time. 33% of the time it goes into a second round; in this case, the first cyborg wins 66% of the time and it is a draw 33% of the time.

Thus 66% of the time cyborg 3 wins, 22% of the time cyborg 1 wins, and 11% of the time its a draw.

for the number one(ive heard this one so many times im not gonna answer it)

and for my favorite riddle that ive heard so far(bewarned, its very hard-if youve heard it before and thus already know the answer please let other solve it :) )

Two twins, we will call them Arrow and Rune have an upcomming birthday, the 16th accually. Early on the day of Arrow's birthday he gets up, and has his parents drive him over to the DMV to get her drivers permit. Rune goes along too. The lady asks if Rune will be getting a permit too. "No" the mom replies "Although they are twins, Rune's birthday isnt for another two days. The strange thing is - Rune was born first!" - Explain

To summierze: Two twins(they are eachothers twin). Younger twin turns 16. Older twin's 16th birthday isnt for another two days. How can this be?


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