LaceyJade wrote:
o_0 wrote:
LaceyJade wrote:
M. Bison wrote:
Trick wrote:
(*Dranzer*) wrote:
Its 1/7.
Pick any day.
That day has 1 out of 7 chances to be picked again.
Each day has a 1/7 chance.
7/49= 1/7.
You only calculate probabilities like this if you're saying "what is the probability that one president or the other dies on a Friday" not "what is the probability that both presidents die on a Friday".
An addition of probabilities like that is an AND calculation, so you use multiplication... 1\7 * 1\7 = 1\49 like LaceyJade said.
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...good grief, I remembered maths :0
The chance of two people dying on the same day is 1/7. There is no probability involving the day of Lincoln's death, as it does not matter. To fulfill the condition, Kennedy has to die the same day Lincoln did. And he had a 1/7 chance of doing so.
No, because Lincoln had to die on the same day Kennedy died, too. Since there are 7 days in the week, and Lincoln died on one of them. So you get 1/7 from there. The probability of Kennedy dying on ANY day is also 1/7. If you multiply them together, you get 1/49, which is the probability of both dying on the same day.
But Lincoln could have died on any day, as he did not need to fulfill a requirement set before him, like Kennedy did. o.o
If Kennedy had to die on the same day Lincoln did, then Lincoln had to have died on the same day Kennedy did, no? AB = BA.
Okay, let's explain it simply.
Lincoln died on, what? A Friday? Let's say so.
So Kennedy could have died on a Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, or Sunday. The odds of him dying on the same day as Lincoln are 1/7. If Lincoln died on a Tuesday, a Thursday, or a Saturday, it wouldn't matter - the odds would still be the same. Have you done probability yet in math class?