zorg wrote:
^_^ I cant table this answer..
A farmer buys 100 live animals for $100, how many of each does he buy if chickens are 50cents each, goats are 3.50 each and sheep are $10 each.
Theres loads of different answers yeh?
Show how a table can be used to solve this question
I hate tables, why couldn't he just buy 10 goddamn sheep and be done with it!
Well this is how I see it -
All the solutions can be sorted into 11 sections - solutions with no sheep, one sheep, two sheep etc. until you get to 10 sheep.
For no goats we have $100 left and we can split this further into 29 solutions, no goats, one goat, two goats etc. until we get to 28 goats and as the number of goats increase obiously the number of chickens decrease.
For one goat we have $90 left and we can split this into 26 solutions - no goats etc. until we reach 25 goats and do te same as above.
For the rest I will just put -
(Number of sheep bought) - (Money left after buying the sheep) - (Number of solutions available for this amount of sheep)
0 - 100 - 29
1 - 90 - 26
2 - 80 - 23
3 - 70 - 21
4 - 60 - 18
5 - 50 - 15
6 - 40 - 12
7 - 30 - 9
8 - 20 - 6
9 - 10 - 3
10- 0 - 0
Total - 162 solutions
The way I worked out the number of solutions for each sheep was for the amount of money available, I divided it by 3.5 to see the maximum amount of goats I could buy with the money and added one for a scenario where no goats where bought.
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I tried to explain it as well as possible but if you still need help just PM me.
The data above could maybe be passed of as a table but I'm too sleepy to think of how else it could be put into a table
